A) 0.01
B) 0.02
C) 0.03
D) 0.04
Correct Answer: A
Solution :
Suppose, D be the diameter of the wire Poissons ratio, \[\sigma =\frac{\text{lateral}\,\,\text{strain}}{\text{longitudinal }\,\text{strain}}\] \[\sigma =\frac{\frac{\Delta D}{D}}{\frac{\Delta L}{L}}\] ?(i) Here: \[\frac{\Delta L}{L}=0.025%=\frac{0.025}{1000}=\frac{1}{40}\] and \[\sigma =0.04\] Putting the given values in Eq. (i) we obtain \[0.4=\frac{\frac{\Delta D}{D}}{\frac{1}{40}}\] or \[\frac{\Delta D}{D}=\frac{1}{40}\times 0.4=0.01%\]
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