A) \[1-\frac{1}{\gamma }\]
B) \[1+\frac{1}{\gamma }\]
C) \[1-\frac{2}{\gamma }\]
D) \[1+\frac{2}{\gamma }\]
Correct Answer: A
Solution :
Heat absorbed by the system at constant pressure \[Q=n{{C}_{p}}\Delta T\]and Change in internal energy \[\Delta U=n{{C}_{V}}\Delta T\] \[W=Q-\Delta U\] Fraction \[=\frac{W}{Q}=\frac{Q-\Delta U}{Q}\] \[=1-\frac{\Delta U}{Q}\] \[=\left( 1-\frac{1}{r} \right)\]
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