A) \[{{F}_{2}},C{{l}_{2}}\]and \[B{{r}_{2}}\]
B) \[C{{l}_{2}},{{F}_{2}}\]and \[B{{r}_{2}}\]
C) \[C{{l}_{2}},B{{r}_{2}}\]and \[{{F}_{2}}\]
D) \[B{{r}_{2}},C{{l}_{2}}\]and \[{{F}_{2}}\]
Correct Answer: B
Solution :
The electron affinity (in kJ/mol) of Fluorine = 332.6 Chlorine =348.5 Bromine =324.7 Iodine =295.5 Chlorine has highest electron affinity value then fluorine then bromine then iodine .X. So, according to question the correct order of electron affinity will be: \[\text{C}{{\text{l}}_{\text{2}}}\,\text{}\,{{\text{F}}_{\text{2}}}\,\text{ B}{{\text{r}}_{\text{2}}}\]
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