EAMCET Medical EAMCET Medical Solved Paper-2003

  • question_answer
    In the reaction : \[{{B}_{2}}{{H}_{6}}+2KOH+2X\to 2Y+6{{H}_{2}}\]X and Y are respectively:

    A)  \[{{H}_{2}},{{H}_{3}}B{{O}_{3}}\]            

    B)   \[HCl,\text{ }KB{{O}_{3}}\]

    C)  \[{{H}_{2}}O,KB{{O}_{3}}\]        

    D)  \[{{H}_{2}}O,KB{{O}_{2}}\]

    Correct Answer: D

    Solution :

                     When diboranes reacts with aqueous solution of alkali they form metaborates and hydrogen gas is evolved. \[{{B}_{2}}{{H}_{6}}+2KOH+\underset{(X)}{\mathop{2{{H}_{2}}O}}\,\xrightarrow{{}}+\underset{\begin{smallmatrix}  \text{Pott}\text{.}\,\text{Metaborate} \\  \text{(Y)}\,\,\text{+}\,\text{6}{{\text{H}}_{\text{2}}} \end{smallmatrix}}{\mathop{2KB{{O}_{2}}}}\,\] So, X is water and Y is potassium metaborate.


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