A) \[BeC{{l}_{2}},s{{p}^{2}},\]linear
B) \[BeC{{l}_{2}},\text{ }s{{p}^{2}},\]triangular planar
C) \[BC{{l}_{3}},\text{ }s{{p}^{2}},\]triangular planar
D) B \[BC{{l}_{3}},s{{p}^{3}},\] tetrahedral
Correct Answer: C
Solution :
\[\text{BeC}{{\text{l}}_{\text{2}}}\]has only 2 bond pair electrons. So, its hybridisation will be sp and structure is linear. In \[\text{BC}{{\text{l}}_{\text{3}}}\] there is 3 bond pair of electrons. So, its hybridisation is \[s{{p}^{2}}\]and bond angle is \[\text{12}{{\text{0}}^{\text{o}}}\] and its shape is trigonal planar.
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