A) \[CHCl{{3}_{{}}}\]
B) \[{{C}_{2}}{{H}_{5}}OH\]
C) \[HCOOH\]
D) \[C{{H}_{3}}CHO\]
Correct Answer: A
Solution :
Chloroform on reaction with sodium ethoxide gives ethyl ortho formate \[[CH{{(O{{C}_{2}}{{H}_{5}})}_{3}}].\] \[CHC{{l}_{3}}+3{{C}_{2}}{{H}_{5}}ONa\xrightarrow{{}}\underset{\text{Ethyl}\,\text{ortho}\,\text{formate}}{\mathop{CH{{(O{{C}_{2}}{{H}_{5}})}_{3}}}}\,+3NaCl\]
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