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EAMCET Medical EAMCET Medical Solved Paper-2003

  • question_answer
    A bird of mass 1.23 kg is able to hover by imparting a downward velocity of 10 m/s uniformly to air of density  \[\rho kg/{{m}^{3}}\]over an effective area \[0.1{{m}^{2}}\]If the acceleration due to gravity is \[10.m/{{s}^{2}},\]then the magnitude of \[\rho \]is in \[kg/{{m}^{3}}\]:

    A)  0.0123                                 

    B)  0.123

    C)  1.23                                      

    D)  1.32

    Correct Answer: C

    Solution :

                     Given: Mass of bird m = 1.25 kg Velocity v =10m/s Area,  \[A=0.1\,{{m}^{2}}\] The density is given by \[\rho =\frac{Mass}{Volume}=\frac{M}{V}=\frac{M}{Av}\]                          \[(\because V=Av)\] \[=\frac{12.3}{0.1\times 10}=1.23\,kg/{{m}^{3}}\]


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