A) \[x=3,\,y=5,\,z=2\]
B) \[x=4,\,y=8,\,z=5\]
C) \[x=8,\,y=4,\,z=4\]
D) \[x=5,\,y=3,\,z=4\]
Correct Answer: C
Solution :
The equation is \[{{H}_{2}}S{{O}_{4}}+xHl\xrightarrow{{}}{{H}_{2}}S+y{{l}_{2}}+z{{H}_{2}}O\] The above equation is balanced by oxidation number method. In this firstly we calculate the change in oxidation number of sulphur and then balance \[{{\text{I}}_{\text{2}}}\] and \[{{\text{H}}_{\text{2}}}\text{O}\text{.}\] According to number of atoms \[\underset{\uparrow 8{{e}^{-}}}{\mathop{\overset{+6}{\mathop{{{H}_{2}}S{{O}_{4}}}}\,}}\,+\underset{1{{e}^{-}}\times \,8}{\overset{+1-1}{\mathop{HI}}}\,\to {{H}_{2}}{{S}^{-2}}+\text{I}_{2}^{0}+{{H}_{2}}O\] \[{{H}_{2}}S{{O}_{4}}+8HI\xrightarrow{{}}{{H}_{2}}S+4{{I}_{2}}+4{{H}_{2}}O\] So, the value of \[x,y\]and z will be 8, 4 and 4 respectively.
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