A) 8, 26, 10
B) 10, 24, 20
C) 8, 22, 24
D) 12, 20, 22
Correct Answer: B
Solution :
The atomic number of cesium is 55. The electronic configuration of cesium atom is \[{{\,}_{55}}Cs=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}4{{s}^{2}},3{{d}^{10}}\] \[4{{p}^{6}},5{{s}^{2}}4{{d}^{10}},5{{p}^{6}},6{{s}^{1}}\] \[=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},\] \[4{{s}^{2}}4{{p}^{6}}4{{d}^{10}},5{{s}^{2}}5{{p}^{6}},6{{s}^{1}}\] The electronic configuration of cesium ion will be \[C{{s}^{+}}=1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}3{{d}^{10}},\] \[4{{s}^{2}}4{{p}^{6}}4{{d}^{10}},5{{s}^{2}}5{{p}^{6}},6{{s}^{0}}\] So, the total number of s electrons = 10 the total number of p electrons = 24 Total number of d electrons = 20
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