A) 294
B) 147
C) 49
D) 24.5
Correct Answer: C
Solution :
The reaction of dichromate ion with ferrous ion in acidic medium takes place as: \[6F{{e}^{2+}}+C{{r}_{2}}O_{7}^{2-}+14{{H}^{+}}\xrightarrow{{}}\] \[6{{F}^{3+}}+2C{{r}^{3+}}+7{{H}_{2}}O\] Total change in oxidation state of iron is \[\overset{+12}{\mathop{6F{{e}^{2+}}}}\,\xrightarrow{{}}\overset{+18}{\mathop{6F{{e}^{3+}}}}\,\] Total change = + 6 So, gram equivalent weight of \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}\] \[\text{=}\,\,\frac{\text{294}}{\text{Total}\,\text{change}\,\text{in}\,\text{O}\text{.S}}\] \[=\frac{294}{6}=49\,g\]
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