A) Na/liquid \[\text{N}{{\text{H}}_{\text{3}}}\]
B) Cold HI
C) \[{{H}_{2}}S{{O}_{4}}/\]high pressure
D) \[A{{l}_{2}}{{O}_{3}}\]heat
Correct Answer: A
Solution :
When diethyl ether is reduced with reducing agent like \[\text{Na/liq}\text{.N}{{\text{H}}_{\text{3}}}\text{,}\]the products obtained are ethane and ethanol. \[{{C}_{2}}{{H}_{5}}-H\xrightarrow{Na.liq.N{{H}_{3}}}\] \[\underset{Ethane}{\mathop{{{C}_{2}}{{H}_{6}}}}\,+\underset{Ethanol}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,\]
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