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EAMCET Medical EAMCET Medical Solved Paper-2003

  • question_answer
    An X- ray tube is operated at a constant potential difference and it is required to get X-ray of wavelength, not less than 0.2 nanometre. Then, the potential difference in kV is: \[(h=6.63\times {{10}^{-34}}J-s,\]\[e=1.6\times {{10}^{-19}}C,\]\[c=3\times {{10}^{8}}m/s)\]

    A)  24.8                                      

    B)  12.4

    C)   6.2                                       

    D)  3.1

    Correct Answer: C

    Solution :

                     Given : Minimum wavelength of X-ray \[\lambda =0.2\times {{10}^{-9}}m\]and \[h=6.63\times {{10}^{-34}}\,Js.\] \[e=1.6\times {{10}^{-19}}\]coulomn                 and        \[e=3\times {{10}^{8}}\,m/s\] The minimum wavelength of continuous X-ray spectrum \[{{\lambda }_{\min }}=\frac{hc}{eV}\] \[V=\frac{hc}{e{{\lambda }_{\min }}}\] \[=\frac{6.63\times {{10}^{-34}}\times 3\times {{10}^{8}}}{1.6\times {{10}^{-19}}\times 0.2\times {{10}^{-9}}}\] \[=6.2\times {{10}^{2}}=6.2\times {{10}^{3}}\,\text{volt}\] \[=6.2\,kV\]


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