A) \[\frac{{{\mu }_{0}}}{4\pi }\frac{M}{{{d}^{3}}}\]
B) \[\frac{{{\mu }_{0}}}{4\pi }\frac{2M}{{{d}^{3}}}\]
C) \[\frac{{{\mu }_{0}}}{4\pi }\frac{3M}{{{d}^{3}}}\]
D) zero
Correct Answer: A
Solution :
According to the condition of the question. Every comer of square exists on the equatorial time of the bar magnet. We know that magnet field on the equatorial line of the bar magnet is given by \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{M}{{{d}^{3}}}\]
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