EAMCET Medical EAMCET Medical Solved Paper-2003

  • question_answer
    In foucaults rotating mirror experiment to determine the velocity of light in air, the distance of the rotating mirror from the concave mirror is 6000 m. The reflected ray is displaced through an angle of \[48\pi \times {{10}^{-3}}\]rad. If the velocity of light in air is \[3\times {{10}^{8}}ms,\] the number of rotations made by the rotating mirror in 1 min, are:

    A)  3,000                                   

    B)  9,000   

    C)  18,000                                 

    D)  36,000

    Correct Answer: C

    Solution :

                     Given: Velocity of light \[c=3\times {{10}^{8}}\,m/s\] \[2\theta =48\pi \times {{10}^{-3}}\,\text{rad}\] \[\Rightarrow \]               \[\theta =24\pi \times {{10}^{-3}}\,\text{rad}\] Distance of rotating mirror from concave mirror d = 6000 m Velocity of light in air is, \[c=\frac{4\pi nd}{\theta }\] or \[n=\frac{c\theta }{4\pi d}\] Putting, given values in above expression \[n=\frac{3\times {{10}^{8}}\times 24\pi \times {{10}^{-3}}}{4\pi \times 6000}=300\,\]turn/s For one minute number of turn will be = 300 x 60 = 18000 turns/min


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