A) \[0.01m{{s}^{-2}}\]
B) \[0.02m{{s}^{-2}}\]
C) \[0.03m{{s}^{-2}}\]
D) \[0.04m{{s}^{-2}}\]
Correct Answer: B
Solution :
Time taken in covering a distance of 3.06 m is \[\text{t =}\frac{\text{Distance}}{\text{Average velocity}}=\frac{3.06}{0.34}=9s\] Also, change in velocity \[v-u=0.18\,m{{s}^{-1}}\] From first law of motion \[v=u+at\] \[\Rightarrow \] \[a=\frac{v-u}{t}=\frac{0.18}{9}=0.02\,m{{s}^{-2}}\]You need to login to perform this action.
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