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EAMCET Medical EAMCET Medical Solved Paper-1999

  • question_answer
    From  the  following  data  for the decomposition of \[{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{4}}}\] at \[\text{30}{{\,}^{\text{o}}}\text{C}\] find out the rate constant (in \[\text{mi}{{\text{n}}^{-1}}\]) Volume of \[{{\text{O}}_{\text{2}}}\] after 10 minutes of the reaction = 90 mL Volume of \[{{\text{O}}_{\text{2}}}\] after completion of the reaction =100 mL:                 

    A)  2.303                                   

    B)  0.2303       

    C)  0.02303               

    D)  23.03

    Correct Answer: B

    Solution :

                     Decomposition of \[{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}}\]is a first order reaction. \[K=\frac{2.303}{t}\log \frac{a}{(a-x)}\]where a = Initial concentration \[(a-x)=\]Remaining concentration or  \[t=\frac{2.303}{k}\log \frac{a}{(a-x)}\]                 For 90% completion of the reaction                 \[{{t}_{90%}}=\frac{2.303}{k}\log \frac{100}{100-90}\] \[=\frac{2.303}{k}\log 10\]                           \[(\because \,{{t}_{90%}}=10\min )\] \[10=\frac{2.303}{k}\log 10\] \[k=\frac{2.303}{10}=0.2303\,{{\min }^{-1}}\]


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