2. Solved Papers
  3. EAMCET Medical

EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    If an organism with a genotype Aa Bb Cc Dd is test crossed, how many different phenotypes can appear in the progeny?

    A)  4                                            

    B)  8

    C)  12                                         

    D)  16

    Correct Answer: D

    Solution :

                     The number of gametes formed in a heterozygous = 2, where n represents the heterozygous alleles. In Aa Bb Cc Dd n = 4 so number of gamete, will be\[={{2}^{4}}=16\].


You need to login to perform this action.
You will be redirected in 3 sec spinner