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EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    An organ pipe \[{{P}_{1}}\] closed at one and vibrating in its first overtone and another pipe \[{{P}_{2}}\], open at both ends vibrating in its third overtone are in resonance with a given tuning fork. Then the ratio of lengths of \[{{P}_{1}}\] and \[{{P}_{2}}\], respectively are given by:

    A)  1 : 2                                      

    B)  1 : 3

    C)  3 : 8

    D)  3 : 4

    Correct Answer: C

    Solution :

                     First overtone of closed end pipe \[{{P}_{2}}\] = Third overtone of open end pipe\[{{P}_{2}}\] \[3\times \frac{v}{4{{l}_{c}}}=4\times \frac{v}{2{{l}_{o}}}\] \[\frac{{{l}_{o}}}{{{l}_{o}}}=\frac{3}{4}\times \frac{2}{4}=3:8\]                                   


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