A) \[{{C}_{2}}{{H}_{5}}NC\]
B) \[{{C}_{2}}{{H}_{5}}CN\]
C) \[{{H}_{3}}C-NH-C{{H}_{3}}\]
D) \[{{C}_{2}}{{H}_{5}}N{{H}_{2}}\]
Correct Answer: B
Solution :
Ethyl chloride with AgCN forms ethyl isocyanide. The functional isomer of ethyl isocyanide is ethyl cyanide. \[{{C}_{2}}{{H}_{5}}Cl+AgCN\xrightarrow{{}}\underset{\text{Ethyl}\,\text{isocyanide}}{\mathop{{{C}_{2}}{{H}_{5}}NC}}\,+AgCl\] \[{{C}_{2}}{{H}_{5}}NC\](ethyl isocyanide) \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{CN}\] (ethyl cyanide) functional isomer
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