A) \[sp\]
B) \[s{{p}^{2}}\]
C) \[s{{p}^{3}}\]
D) \[s{{p}^{3}}d\]
Correct Answer: C
Solution :
The function of aqueous KOH is to convert halogen to hydroxy group. So, ethyl chloride reacts with aq. KOH to give \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}\]as: \[\begin{matrix} {{C}_{2}}{{H}_{5}} \\ \underset{Aq.}{\mathop{O\overset{+}{\mathop{H}}\,}}\, \\ \end{matrix}\xrightarrow{{}}\underset{\text{Ethyl}\,\text{alcohol}}{\mathop{{{C}_{2}}{{H}_{5}}OH}}\,+KCl\] In \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}\]all the four valencies of carbon are single bonded. So, hybridization of carbon atom in \[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{5}}}\text{OH}\]is \[\text{s}{{\text{p}}^{3}}.\]
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