A) \[{{H}_{2}}C=C{{H}_{2}}\to C{{H}_{3}}C{{H}_{2}}Cl\]
B) \[{{H}_{3}}C-O-C{{H}_{3}}\to C{{H}_{3}}Cl\]
C) \[C{{H}_{3}}C{{H}_{2}}OH\to C{{H}_{3}}C{{H}_{2}}Cl\]
D) \[CH\equiv CH\to C{{H}_{2}}=CHCl\]
Correct Answer: C
Solution :
\[\text{PC}{{\text{l}}_{\text{5}}}\]or \[\text{PC}{{\text{l}}_{\text{3}}}\]reagent are used to convert \[-\text{OH}\] (alcoholic group) to \[-\text{Cl}\] (chloro group) e.g.. \[C{{H}_{3}}-C{{H}_{2}}-OH+PC{{l}_{5}}\xrightarrow{{}}\]\[C{{H}_{3}}C{{H}_{2}}Cl+POC{{l}_{3}}+HCl\]
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