A) \[{{I}_{2}}<ICl<HI<HI{{O}_{4}}\]
B) \[HI{{O}_{4}}<ICl<{{I}_{2}}<HI\]
C) \[{{I}_{2}}<HI<ICl<HI{{O}_{4}}\]
D) \[HI<{{I}_{2}}<ICl<HI{{O}_{4}}\]
Correct Answer: D
Solution :
In \[{{I}_{2}}=0\] In \[ICl=+1\] In \[HI=-1\] In \[\overset{+1}{\mathop{H}}\,I{{\overset{-2}{\mathop{O}}\,}_{4}}=+1+x-8=0\] \[x=+8-1\] \[x=+7\] So the correct order is \[\overset{-1}{\mathop{HI}}\,<{{\overset{0}{\mathop{I}}\,}_{2}}<\overset{+1}{\mathop{IC}}\,l<{{\overset{+7}{\mathop{HIO}}\,}_{4}}\]
You need to login to perform this action.
You will be redirected in
3 sec
