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EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    On passing a current through a \[\text{KCl}\]solution, 19.5 g of potassium is deposited. If the same quantity of electricity is passed through a solution of aluminium chloride, the amount  of aluminium deposited is :

    A)  4.5g                                      

    B)  9.0g

    C)  13.5g                                   

    D)  27g

    Correct Answer: A

    Solution :

                     According to Faradays second law of electrolysis, the amount of different substances deposited by the passage of same quantity of electricity are proportional to their chemical equivalent weights. \[W\propto E\] \[\frac{{{W}_{1}}}{{{W}_{2}}}=\frac{{{E}_{1}}}{{{E}_{2}}}\] \[{{W}_{KCl}}=19.5g;{{E}_{{{K}^{+}}}}=39\] \[{{W}_{AlC{{l}_{3}}}}=?;{{E}_{A{{l}^{3+}}}}=\frac{27}{3}=9\]                 then ,                    \[\frac{19.5}{x}=\frac{39}{9}\] \[x=\frac{19.5\times 9}{39}=4.5\,g\]                 So, 4.5 g of aluminium is deposited.


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