A) n = 2 to n =3
B) n = 4 to n = 3
C) n = 3 to n = 2
D) n = 2 to n = 1
Correct Answer: B
Solution :
In atoms, as the number of shell increases, the energy differences between the shells decreases. It means that the energy difference between \[{{n}_{1}}\] and \[{{n}_{2}}\]is higher than between \[{{n}_{2}}\]and \[{{n}_{3}}\] and in the same way energy difference is more between \[{{n}_{2}}\]and \[{{n}_{3}}\]than between \[{{n}_{3}}\]and \[{{n}_{4}}.\] We know that,\[E=hv=\frac{hc}{\lambda }\]wave length is inversely proportional to energy difference. So, in the given alternates wave length is maximum between \[{{n}_{4}}\]to \[{{n}_{3}}\] because between \[{{n}_{4}}\]and \[{{n}_{3}}\] energy difference is minimum.
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