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EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    The   \[\text{ }\!\!\Delta\!\!\text{ H}\]   value   for   the   reaction \[{{\text{H}}_{\text{2}}}\text{+}\,\text{C}{{\text{l}}_{\text{2}}}\text{= 2HCl}\,\]is \[-\,44.12\,kcal.\]If \[{{\text{E}}_{\text{1}}}\]is the activation energy of the reactants and \[{{\text{E}}_{2}}\] is the activation energy of the products, then for the above reaction :

    A)  \[{{E}_{1}}>{{E}_{2}}\]                 

    B)  \[{{E}_{1}}<{{E}_{2}}\]

    C)   \[{{E}_{1}}={{E}_{2}}\]                

    D)   \[\Delta H\] is not related of \[{{E}_{1}}>{{E}_{2}}\]

    Correct Answer: B

    Solution :

                     The given equation is : \[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl,\Delta \Eta =-44.12\,\text{kcal}\] or \[{{H}_{2}}+C{{l}_{2}}\xrightarrow{{}}2HCl+44.12\,\text{kcal}\] The above equation is an example of exothermic reaction as energy is released in the equation. Energy is released only when reactants have less energy than products. So,


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