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EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    In the following reaction, the energy released is: \[{{4}_{1}}\,{{H}^{1}}\,\to {{\,}_{2}}H{{e}^{4}}+2{{e}^{+}}+energy\]

    A)  12.33 MeV                        

    B)  25.75 MeV

    C)   37MeV                              

    D)  49.35 MeV

    Correct Answer: B

    Solution :

                     The reaction is given as \[4{{\,}_{1}}{{H}^{1}}\to {{\,}_{2}}H{{e}^{4}}+2{{\,}_{1}}e{{\,}^{o}}+energy\] \[4{{\,}_{1}}{{H}^{1}}=4.030372\,\text{amu}\] \[{{\,}_{2}}H{{e}^{4}}=4.002604\,\text{amu}\] \[2\,{{\,}_{1}}{{e}^{o}}=0.001098\,\text{amu}\]                 Loss in mass or mass defect                 \[=4.0303720-(4.002604+0.001098)\] \[=0.02667\] Energy released \[=0.02667\times 931\]                 \[=24.83\,\text{MeV}\]


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