A) \[6.2\times {{10}^{16}}/s\]
B) \[6.2\times {{10}^{15}}/s\]
C) \[1.56\times {{10}^{16}}/s\]
D) \[3.12\times {{10}^{16}}/s\]
Correct Answer: D
Solution :
From relation \[P=\frac{nE}{t}\left( \begin{align} & Here: \\ & n=no.\,of\,released \\ & E=energy\,released\, \\ \end{align} \right)\] \[n=\frac{Pt}{E}=\frac{{{10}^{6}}}{200\times {{10}^{6}}\times 1.6\times {{10}^{-19}}}\] \[n=3.125\times {{10}^{6}}\sec \]
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