EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    An electron beam is allowed to pass normally through magnetic and electric fields which are mutually perpendicular. When the magnetic field induction and electric field strength are \[0.0004\text{ }Wb/{{m}^{2}}\]and 3000 V/m respectively, the beam suffers no deflection. Then the velocity of electron is:

    A)  \[7.5\,\times \,{{10}^{6}}\,m/s\]                             

    B)  \[7.5\,\times \,{{10}^{4}}\,m/s\]

    C)  \[1.56\,\times \,{{10}^{16}}\,/s\]                            

    D)  \[3.12\,\times \,{{10}^{16}}\,/s\]

    Correct Answer: A

    Solution :

                     If the electron beam has no deflection in electric and magnetic field, then force due to electric field is equal to force due to magnetic field, then the velocity of electron \[v=\frac{E}{B}\left( \begin{align}   & \text{Given:}B=0.0004\,W/{{m}^{2}} \\  & E=3000\,\text{V/m} \\ \end{align} \right)\] \[v=\frac{3000}{0.0004}\] \[=7.5\times {{10}^{6}}m/s\]


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