A) \[4.16\times {{10}^{-34}}\]
B) \[3.32\times {{10}^{-34}}\]
C) \[1.04\times {{10}^{-34}}\]
D) \[2.08\times {{10}^{-34}}\]
Correct Answer: C
Solution :
Angular momentum of electron\[L=\frac{nh}{2\pi }\]Since, electron in hydrogen atom is excited from \[{{n}_{1}}=4\] stationary orbit to \[{{n}_{2}}=5\]stationary orbit\[{{L}_{5}}-{{L}_{4}}=\frac{({{n}_{2}}-{{n}_{1}})}{2\pi }=\frac{(5-4)}{2\pi }h\]\[=\frac{6.64\times {{10}^{-34}}}{2\times 3.14}=1.05\times {{10}^{-34}}\]
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