2. Solved Papers
  3. EAMCET Medical

EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    A constant torque of 1000 N-m turns a wheel of moment of inertia \[200\text{ }kg-{{m}^{2}}\]about an axis through its centre. Its angular velocity after 3 second is, in rad/s:

    A)  1                                            

    B)  5

    C)  15                                         

    D)  10

    Correct Answer: C

    Solution :

                     The formula for torque is as \[\tau =I\alpha \]where \[I\] is moment of inertia and \[\alpha \] is the angular acceleration \[\alpha =\frac{\tau }{I}=\frac{1000}{200}=5\,\,rad/{{s}^{2}}\] \[\left( \begin{align}   & \text{Given:}\,\tau \,=1000N \\  & I\text{ }=\text{ }2000\,kg-{{m}^{2}} \\  & \text{t = 3s } \\ \end{align} \right)\] Now, angular velocity \[\omega =\alpha \,t=5\times 3\] \[=15\,rad/s\]


You need to login to perform this action.
You will be redirected in 3 sec spinner