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EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    The weight of a man in a lift, moving upwards is 608 N while the weight of the same man in the lift moving downwards, with the same acceleration, is 368 N. His normal weight in newton is:

    A)  488                                       

    B)  588

    C)  480                                       

    D)  240

    Correct Answer: A

    Solution :

                     If the lift is moving upwards with acceleration a, then \[m(g+a)=608\,\text{N}\]                            ?(i) If the lift is moving downwards with an acceleration a, then \[m(g-a)=368N\]                              ?(ii) Now, adding Eqs. (i) and (ii), we get \[2mg=608+368=976\]   \[mg=488\,kg\]


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