A) \[\frac{3}{\sqrt{2}}\]north - east
B) \[3\sqrt{2}\] north - east
C) \[\frac{3}{\sqrt{2}}\]north - west
D) \[3\sqrt{2}\]north - west
Correct Answer: C
Solution :
Average acceleration of the particle is given by \[\text{=}\frac{\text{Change}\,\text{in}\,\text{velocity}}{\text{Time}}\] \[=\frac{\sqrt{{{(15)}^{2}}+{{(15)}^{2}}}}{10}\] \[=\frac{15\sqrt{2}}{10}\] \[=\frac{3}{\sqrt{2}}\] (towards north - west)
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