EAMCET Medical EAMCET Medical Solved Paper-1997

  • question_answer
    If M, L, T and I stand for mass, length, time and electric current respectively, the dimensional formula for capacitance is:

    A)  \[\left[ {{M}^{-1}}{{L}^{2}}{{T}^{-4}}{{I}^{2}} \right]\]                    

    B)  \[\left[ {{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{I}^{2}} \right]\]

    C)  \[\left[ M{{L}^{2}}{{T}^{4}}{{I}^{2}} \right]\]                      

    D)  \[\left[ M{{L}^{2}}{{T}^{-4}}{{I}^{-2}} \right]\]

    Correct Answer: C

    Solution :

                     Capacitance \[C=\frac{Ch\arg e}{Potential}=\frac{q}{V}=\frac{Q}{W/q}=\frac{{{q}^{2}}}{W}\] Dimensions of \[\text{C = }\frac{{{\text{(Dimensions}\,\text{of}\,\text{charge)}}^{\text{2}}}}{\text{Dimensions}\,\text{of}\,\text{work}}\] \[=\frac{{{[IT]}^{2}}}{[M{{L}^{2}}{{T}^{-2}}]}\] \[=\frac{[{{I}^{2}}{{T}^{2}}]}{[M{{L}^{2}}{{T}^{-2}}]}\] \[=[{{M}^{-1}}{{L}^{-2}}{{T}^{4}}{{I}^{2}}]\]


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