A) a deep blue solution is obtained
B) a blue precipitate of \[Cu{{(OH)}_{2}}\] is obtained
C) a black precipitate of CuO is obtained
D) No change takes place
Correct Answer: A
Solution :
\[CuS{{O}_{4}}+N{{H}_{4}}OH\xrightarrow{{}}\underset{cuprir\text{ }hydroxide}{\mathop{Cu{{(OH)}_{2}}}}\,\] \[Cu{{(OH)}_{2}}+N{{H}_{4}}OH\xrightarrow{{}}\] \[\underset{\begin{smallmatrix} tetraamminecopper\text{ }\left( II \right)\text{ }sulphate \\ \left( deep\text{ }blue\text{ }solution \right) \end{smallmatrix}}{\mathop{[Cu{{(N{{H}_{3}})}_{4}}\,|\,S{{O}_{4}}}}\,\]
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