A) \[C{{o}^{3+}}\], octahedral complex with weak field ligands
B) \[C{{o}^{3+}}\], octahedral complex with strong field ligands
C) \[C{{o}^{2+}}\]in tetrahedral complex
D) \[C{{o}^{2+}}\]in square planar complex
Correct Answer: B
Solution :
\[C{{o}^{3+}}=[Ar]3{{d}^{6}}4{{s}^{0}}\] In the presence of strong field ligands, pairing occurs. Thus, \[C{{o}^{3+}}\] (in presence = [Ar]
of strong (no unpaired electrons) field ligand) Thus, it is diamagnetic in nature. (Note: \[C{{o}^{2+}}\] always contains an unpaired electron.)
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