question_answer

The hybridisation in \[{{[Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\] is

A)  \[ds{{p}^{3}}\]

B)  \[s{{p}^{3}}{{d}^{2}}\]

C)  \[s{{p}^{3}}\]    

D)  \[{{d}^{2}}s{{p}^{3}}\]

Correct Answer: D

Solution :

In \[{{(Co{{(N{{H}_{3}})}_{6}}]}^{3+}}\], Co is present as \[C{{o}^{3+}}\]. \[_{27}CO=[Ar]3{{d}^{7}}4{{s}^{2}}\] \[C{{O}^{3+}}=[Ar]\] \[{{[CO{{(N{{H}_{3}})}_{6}}]}^{3+}}=[Ar]\]