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DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    As \[{{O}_{2}}(l)\] is cooled at 1 atm pressure, it freezes to form solid I at 54.5 K. At a lower temperature, solid I rearranges to solid II, which has a different crystal structure.    Thermal measurements show that for the phase transition solid I to solid \[II,\,\Delta H=-743.1\,J\,mo{{l}^{-1}}\]and\[\Delta S=-17.0\,\,J{{K}^{-1}}\,mo{{l}^{-1}}\]. At what temperature are solids I and II in equilibrium?

    A)  2.06 K

    B)  31.5 K

    C)  43.7 K

    D)  53.4 K

    Correct Answer: C

    Solution :

    For equilibrium, \[\Delta G=0\] \[\therefore \] \[\Delta H=T\Delta \,S\] \[T=\frac{\Delta H}{\Delta S}\] \[\frac{-743.1\,\,J\,mo{{l}^{-1}}}{-17.0\,\,J\,{{K}^{-1}}mo{{l}^{-1}}}=43.71\,K\]


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