A) \[8.18\times {{10}^{-31}}m\]
B) \[6.26\times {{10}^{-21}}m\]
C) \[4.93\times {{10}^{-7}}m\]
D) \[4.11\times {{10}^{-6}}m\]
Correct Answer: C
Solution :
Given, Cl ? Cl bond energy = 243 kJ/mol \[=\frac{243\times {{10}^{3}}}{6.023\times {{10}^{23}}}J/atom\] \[E=\frac{hc}{\lambda }\] \[=\frac{243\times {{10}^{3}}}{6.023\times {{10}^{23}}}=\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}}{\lambda }\] \[\lambda =\frac{6.6\times {{10}^{-34}}\times 3\times {{10}^{8}}\times 6.023\times {{10}^{23}}}{243\times {{10}^{3}}}\] \[=\frac{119.26\times {{10}^{-3}}}{243\times {{10}^{3}}}=4.907\times {{10}^{7}}m\] \[\approx 4.93\times {{10}^{-7}}m\]
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