A) \[1.4\times {{10}^{-8}}M\]
B) \[1.2\times {{10}^{-4}}M\]
C) \[1.9\times {{10}^{-4}}M\]
D) \[3.7\times {{10}^{-4}}M\]
Correct Answer: B
Solution :
\[[{{H}^{+}}]=C\alpha \] \[=C\sqrt{\frac{{{K}_{a}}}{C}}\] \[=\sqrt{{{K}_{a}}\,.\,C}\] \[=\sqrt{3.5\times {{10}^{-8}}\times 0.40}\] \[=\sqrt{1.4\times {{10}^{-8}}}\] \[=1.2\times {{10}^{-4}}M\]
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