A) Its volume will become greater by a factor of 2.5
B) Its Volume will become greater by a factor of 1.6
C) Its volume will become greater by a factor of 1.1
D) Its volume will become smaller by a factor of 0.70
Correct Answer: B
Solution :
Let volume of air bubble under water = V Volume of bubble at surface \[={{V}_{1}}\] Given, temperature under water, \[{{T}_{1}}=15+273=288\,K\] pressure under water, \[{{p}_{1}}=1.5\]atm temperature at surface, \[{{T}_{2}}=25+273=298\,K\] pressure at the surface, \[{{p}_{2}}=1.0\] atm We know that, \[\frac{{{p}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{p}_{2}}{{V}_{2}}}{{{T}_{2}}}\] On putting values, we get \[\frac{1.5\times V}{288}=\frac{1.0\times {{V}_{1}}}{298}\] or \[\frac{V}{{{V}_{1}}}=\frac{288\times 1.0}{298\times 1.5}\] \[\frac{V}{{{V}_{1}}}=0.64\] or \[{{V}_{1}}=\frac{V}{0.64}\] = 1.64 V Thus, the volume will become greater by a factor of 1.6.
You need to login to perform this action.
You will be redirected in
3 sec
