A) \[2.3\times {{10}^{-3}}\]
B) \[2.3\times {{10}^{-4}}\]
C) \[2.0\times {{10}^{-4}}\]
D) \[2.0\times {{10}^{-6}}\]
Correct Answer: B
Solution :
\[{{K}_{a}}=C\,\,{{\alpha }^{2}}/(1/\alpha )\] where, C = concentration = 0.01 M \[\alpha =\] degree of dissociation = 14% = 0.14 \[{{K}_{a}}=0.01\times {{(0.14)}^{2}}/(1-0.14)\] \[=\frac{1.96\times {{10}^{-4}}}{0.86}\] \[=2.27\times {{10}^{-4}}\approx 2.3\times {{10}^{-4}}\]
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