A) [A] only
B) [A] and [B] only
C) [A] and [C] only
D) [A], [B] and [C]
Correct Answer: C
Solution :
A curve between vapour pressure and temperature gives the value of normal boiling point while a graph between In p and 1/T gives the value of enthalpy of vaporisation. \[In\,\,p=-\frac{\Delta \,\,{{H}_{v}}}{R}\left( \frac{1}{T} \right)+\frac{\Delta \,\,{{S}_{v}}}{R}\] where, p = vapour pressure \[\Delta \,\,{{H}_{v}}=\] enthalpy of vaporisation.
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