A) \[T\sqrt{2}\]
B) infinite
C) \[T/\sqrt{2}\]
D) zero
Correct Answer: C
Solution :
When the elevator is at rest, its time period is given by \[T=2\pi \sqrt{\frac{I}{g}}=2\pi \sqrt{\frac{I}{10}}\] When the elevator accelerates upwards, its time period becomes . \[T=2\pi \sqrt{\frac{I}{g+a}}=2\pi \sqrt{\frac{I}{10+10}}\] \[=2\pi \sqrt{\frac{I}{20}}=2\pi \sqrt{\frac{I}{10}}\times \frac{1}{\sqrt{2}}=\frac{T}{\sqrt{2}}\]
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