A) \[C{{H}_{2}}OHC{{H}_{2}}C{{H}_{2}}COOH\]
B) \[C{{H}_{3}}CHOHC{{H}_{2}}COOH\]
C) \[C{{H}_{3}}C{{H}_{2}}CHOHCOOH\]
D) \[C{{H}_{3}}CHOHCHOHCOOH\]
Correct Answer: A
Solution :
\[\gamma \] or \[\delta \]-hydroxy acids, on heating, give lactones, having same number of carbon atoms as the parent acid. Thus, \[\overset{\gamma }{\mathop{C}}\,{{H}_{2}}OH\overset{\beta }{\mathop{C}}\,{{H}_{2}}\overset{\alpha }{\mathop{C}}\,{{H}_{2}}COOH\] gives five membered lactone. \[\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,{{H}_{2}}C{{H}_{2}}C{{H}_{2}}\,\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,=O\xrightarrow[-{{H}_{2}}O]{\Delta }\]
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