DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    On \[\alpha \]-decay \[_{92}^{238}U\] produces

    A)  \[_{93}^{238}Np\]           

    B)  \[_{90}^{234}Th\]

    C)  \[_{91}^{234}Pa\]          

    D)  \[_{92}^{234}U\]

    Correct Answer: B

    Solution :

    During a-decay, the atomic mass reduces by 4 units while atomic number decreases by 2 units. Thus,\[_{92}^{238}U\xrightarrow{-\alpha {{(}_{2}}H{{e}^{4}})}\,_{90}^{234}Th\]


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