A) 42 K
B) 30 K
C) 20 K
D) 56 K
Correct Answer: A
Solution :
In first cylinder, since the piston is movable \[{{Q}_{1}}=\mu Cp(\Delta {{T}_{1}})\] In second cylinder, since the piston is fixed \[{{Q}_{2}}=\mu {{C}_{v}}(\Delta {{t}_{2}})\] \[\because \] \[{{Q}_{1}}={{Q}_{2}}\] \[{{C}_{p}}\Delta {{T}_{1}}={{C}_{v}}\Delta {{T}_{2}}\] \[\frac{7}{2}\times 30=\frac{5}{2}\times \Delta {{T}_{2}}\] \[{{T}_{2}}=42\,K\]
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