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DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    An ideal gas is made to go through a cyclic thermodynamical process in four steps. The amounts of heat involved are\[{{Q}_{1}}=100\,J,\] \[{{Q}_{2}}=300\,J,\]   \[{{Q}_{2}}=400\,J,\]   and   \[{{Q}_{4}}=100\,J,\] respectively.   The   corresponding   work involved are\[{{W}_{1}}=300\,J,\] \[{{W}_{2}}=-100\,J,\] \[{{W}_{3}}=400\,J\]and \[{{W}_{4.}}\] What is the value of\[{{W}_{4.}}\]?

    A)  100 J  

    B)  - 100 J

    C)  500 J  

    D)  - 700 J

    Correct Answer: D

    Solution :

     The net heat involved is equal to \[Q={{Q}_{1}}+{{Q}_{2}}+ & {{Q}_{3}}+{{Q}_{4}}=100+300-400-100\] \[=-100\] The net work done is equal to \[W={{W}_{1}}+{{W}_{2}}+{{W}_{3}}+{{W}_{4}}\] \[=300-100+400+{{W}_{4}}=600+{{W}_{4}}\] Assuming no heat loss, \[Q=W\] \[\Rightarrow \] \[{{W}_{4}}=-100-600=-700\,J\]


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