DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    10 moles of an ideal monoatomic gas at \[10{}^\circ C\] is mixed with 20 moles of another monoatomic gas at\[20{}^\circ C\]. Then the temperature of the mixture is

    A)  \[15.5{}^\circ C\]

    B)  \[15{}^\circ C\]  

    C)  \[16{}^\circ C\]  

    D)  \[16.6{}^\circ C\]

    Correct Answer: D

    Solution :

     Temperature of the mixture is given by \[T=\frac{{{n}_{1}}{{m}_{1}}+{{n}_{2}}{{m}_{2}}}{{{n}_{1}}+{{n}_{2}}}\] \[T=\frac{10\times 10+20\,\times 20}{10+20}=\frac{500}{30}\approx {{16.6}^{o}}C\]


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