A) 6400 km
B) 2400 km
C) 2946 km
D) 1600 km
Correct Answer: A
Solution :
The acceleration due to gravity at the heigh th \[g=g\frac{g}{{{\left( 1+\frac{h}{{{R}_{e}}} \right)}^{2}}}\] According to the question \[g=\frac{g}{4}\] \[\therefore \] \[\frac{g}{4}=\frac{g}{{{\left( 1+\frac{h}{{{R}_{e}}} \right)}^{2}}}\] \[{{\left( 1+\frac{h}{{{R}_{e}}} \right)}^{2}}=4\] \[1+\frac{h}{{{R}_{e}}}=2\Rightarrow \frac{h}{{{R}_{e}}}=1\] \[h={{R}_{e}}=6400\,km\]
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