2. Solved Papers
  3. DUMET Medical

DUMET Medical DUMET Medical Solved Paper-2010

  • question_answer
    An iron ball of mass M is hanged from the ceiling by a spring with a spring constant k. It executes a SHM with a period P. If the mass of the ball is increased by four times, the new period will be

    A)  4P    

    B)  P/4   

    C)  2P    

    D)  P

    Correct Answer: C

    Solution :

     The time period of the iron ball would be given by, \[P=2\pi \sqrt{\frac{M}{K}}\] So, if mass of the ball is increased to 4 times of its initial mass, then the new period becomes \[P=2\pi \sqrt{\frac{4M}{K}}=2P\]


You need to login to perform this action.
You will be redirected in 3 sec spinner